Peer reviewed by Jonathan Loomes-Vrdoljak on 5 August 2019
Intro to the Kidney MCQ
Question 1 |
Outline, in sequence, the blood supply for the kidney beginning from renal artery to venous supply
Renal artery, segmental artery, interlobar artery, arcuate artery, interlobular artery, afferent arteriole, glomerulus, efferent arteriole, peritubular capillaries/vasa recta. | |
Renal artery, interlobular artery, interlobar artery, arcuate artery, segmental artery, afferent arteriole, glomerulus, peritubular capillaries/vasa recta efferent arteriole | |
Renal artery, segmental artery, interlobular artery, arcuate artery, interlobar artery, afferent arteriole, glomerulus, peritubular capillaries/vasa recta, efferent arteriole | |
Renal artery, segmental artery, interlobular artery, arcuate artery, interlobular artery, afferent arteriole, glomerulus, efferent arteriole, peritubular capillaries/vasa recta. |
Question 2 |
Inulin is one of the most accurate measures of urinary excretion rate, why is this?
It is filtered and partially reabsorbed so it accurately reflects what happens to substances in the filtrate | |
It is filtered only, so its concentration in the urine is proportionate to the amount in the blood | |
It is filtered and secreted, accurately representing how the kidney processes multiple substances as a whole | |
It is filtered and completely reabsorbed, reflecting how glucose is handled by the kidney |
Question 3 |
What are the three components of the glomerular filtration barrier and their filtration characteristics?
Fenestrated endothelium (filters based on size and shape), hepatocytes (filters based on size and shape), type 2 pneumocytes (filters based on size and shape)
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Blood vessel (filters based on charge), glomerulous (filters based on size and shape), bowman’s capsule (filters based on size and shape)
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Fenestrated endothelium (filters based on size and shape), basement membrane (filters based on charge), podocytes (filters based on size and shape)
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2 layers of fenestrated endothelium (filters based on size and shape), Basement membrane (filters based on charge) |
Question 4 |
How would the basement membrane of the glomerular filtration barrier prevent the passage of albumin?
By repulsion of albumin’s positive charge | |
By having fenestrations smaller than the size of albumin | |
By having fenestrations of different shape to albumin | |
By repulsion of albumin’s negative charge
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Question 5 |
What are the main ions contributing to the concentration gradient in extracellular fluid?
Calcium and bicarbonate | |
Potassium, phosphate and inorganic anions | |
Sodium and potassium | |
Sodium and chloride |
Question 6 |
What property of the epithelium in the proximal convoluted tubule is related to its function?
The thin layer of the simple squamous epithelium allows important molecules to diffuse more easily | |
The brush border of cuboidal epithelium maximises the surface area for absorption of molecules | |
The columnar epithelium ensure quick active transport of a high concentration of important molecules across the membrane | |
The stratified squamous epithelium helps to resist the wear and tear of high volume filtrate entering the PCT
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Question 7 |
What type of cell is present in the thick ascending loop of Henle?
Simple squamous | |
Simple cuboidal | |
Ciliated simple cuboidal | |
Simple columnar |
Question 8 |
A patient has nephrogenic diabetes insipidus. Which part of the uriniferous tubule is most likely to be affected?
Proximal convoluted tubule | |
Collecting duct | |
Thick ascending loop of Henle | |
Thick descending loop of Henle |
Question 9 |
Which is not one of the four ways a substance is handled by the kidney?
Filtered | |
Filtered and partially reabsorbed | |
Filtered and completely reabsorbed | |
None of the above
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Question 10 |
How is urinary filtration rate calculated?
Urinary excretion rate = Filtration rate + Secretion rate + Reabsorption rate | |
Urinary excretion rate = Filtration rate - Secretion rate – Reabsorption rate | |
Urinary excretion rate = Filtration rate + Secretion rate – Reabsorption rate | |
Urinary excretion rate = (Filtration rate + Secretion rate) /Reabsorption rate |