Peer reviewed by Jonathan Loomes-Vrdoljak on 5 August 2019
Intro to the Kidney MCQ
Question 1 |
Which of the following is not a function of the kidney?
Calcium homeostasis | |
Regulation of ECF sodium | |
Synthesis of ADH | |
Regulation of body fluid volume |
Question 2 |
Inulin is one of the most accurate measures of urinary excretion rate, why is this?
It is filtered and partially reabsorbed so it accurately reflects what happens to substances in the filtrate | |
It is filtered only, so its concentration in the urine is proportionate to the amount in the blood | |
It is filtered and secreted, accurately representing how the kidney processes multiple substances as a whole | |
It is filtered and completely reabsorbed, reflecting how glucose is handled by the kidney |
Question 3 |
A patient has nephrogenic diabetes insipidus. Which part of the uriniferous tubule is most likely to be affected?
Proximal convoluted tubule | |
Collecting duct | |
Thick ascending loop of Henle | |
Thick descending loop of Henle |
Question 4 |
What property of the epithelium in the proximal convoluted tubule is related to its function?
The thin layer of the simple squamous epithelium allows important molecules to diffuse more easily | |
The brush border of cuboidal epithelium maximises the surface area for absorption of molecules | |
The columnar epithelium ensure quick active transport of a high concentration of important molecules across the membrane | |
The stratified squamous epithelium helps to resist the wear and tear of high volume filtrate entering the PCT
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Question 5 |
How is urinary excretion rate altered by a high reabsorption rate?
It is increased | |
It is decreased | |
It does not alter urinary excretion rate | |
It is not part of the equation |
Question 6 |
What type of cell is present in the thick ascending loop of Henle?
Simple squamous | |
Simple cuboidal | |
Ciliated simple cuboidal | |
Simple columnar |
Question 7 |
How would the basement membrane of the glomerular filtration barrier prevent the passage of albumin?
By repulsion of albumin’s positive charge | |
By having fenestrations smaller than the size of albumin | |
By having fenestrations of different shape to albumin | |
By repulsion of albumin’s negative charge
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Question 8 |
How is urinary filtration rate calculated?
Urinary excretion rate = Filtration rate + Secretion rate + Reabsorption rate | |
Urinary excretion rate = Filtration rate - Secretion rate – Reabsorption rate | |
Urinary excretion rate = Filtration rate + Secretion rate – Reabsorption rate | |
Urinary excretion rate = (Filtration rate + Secretion rate) /Reabsorption rate |
Question 9 |
A decrease in blood flow to an interlobular artery could result from stenosis of which artery?
Arcuate artery | |
Afferent arteriole | |
Efferent arteriole | |
Vasa recta |
Question 10 |
What are the three components of the glomerular filtration barrier and their filtration characteristics?
Fenestrated endothelium (filters based on size and shape), hepatocytes (filters based on size and shape), type 2 pneumocytes (filters based on size and shape)
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Blood vessel (filters based on charge), glomerulous (filters based on size and shape), bowman’s capsule (filters based on size and shape)
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Fenestrated endothelium (filters based on size and shape), basement membrane (filters based on charge), podocytes (filters based on size and shape)
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2 layers of fenestrated endothelium (filters based on size and shape), Basement membrane (filters based on charge) |